[VA] SRC #011 - April 1st, 2022 Bizarro Special

[Albert Chan]

It would be nice to have back of envelope calculation for F

We can keep planet intact, and split the other planet, to 2x2x2 = 8 cubes.
With symmetry, only 1 corner to consider

(3/4, 1/4, 1/4) → D1^2 = 11/16, cos(θ1) = 3/√11
(5/4, 1/4, 1/4) → D2^2 = 27/16, cos(θ2) = 5/√27

Force is proportional to 1/D^2
Force is an vector, we need cos(θ) correction, to sum only force between planets.

F = ((16/11)*(3/√11) + (16/27)*(5/√27)) / 2 ≈ 0.94295

Since 1 planet still intact, we would expect F to be even less, i.e. F < 0.94295