HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x'
|
11-08-2023, 09:14 AM
(This post was last modified: 11-08-2023 12:56 PM by Gil.)
Post: #7
|
|||
|
|||
RE: HP50 : integral of '0^x' gives induly '?`
Ok for the undefined function '0^x'.
But what about the well defined function '0*x'? Integral of (0*x) should be simplified before calculating and (logically?) be equal to integral of (0) = constant (as correctly answers Wolfram Alpha for the aforementioned indefinite integral). Or am I wrong? On the HP50G, however, '0*X' INTVX (with no bounds) gives zero, as it has been initially calculated with a general formulae a*x²/2, and then the factor a is replaced by its original value a=0, which gives a final value of 0, a special case — indeed a correct result when settling real bounds with the HP50G and executing EVAL command or —>NUM command. |
|||
« Next Oldest | Next Newest »
|
Messages In This Thread |
HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x' - Gil - 11-06-2023, 05:05 PM
RE: HP50 : integral of '0^x' gives induly '?` - rawi - 11-07-2023, 02:38 PM
RE: HP50 : integral of '0^x' gives induly '?` - rawi - 11-07-2023, 03:11 PM
RE: HP50 : integral of '0^x' gives induly '?` - klesl - 11-07-2023, 03:28 PM
RE: HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x' - Gil - 11-07-2023, 09:30 PM
RE: HP50 : integral of '0^x' gives induly '?` - klesl - 11-08-2023, 07:52 AM
RE: HP50 : integral of '0^x' gives induly '?` - Gil - 11-08-2023 09:14 AM
|
User(s) browsing this thread: