Cadillac Quadratic Solver behaving like an Edsel - Problem solved!!

[Dieter]

(09-16-2014 01:20 AM)Gerson W. Barbosa Wrote:  You can try
RCLx F
RCL F
ABS
/

Instead of

RCLF
SGN
x

starting at step B0014, assuming F is never zero.

If I understand correctly, the sequence

RCL F
SGN
x

shall be replaced by something that does not require a sign function and that also does not use more than one stack level. Your suggestion will do so, but the combination of a multiplication and a subsequent division may degrade accuracy, and, more important, it will not work for F = 0.

So how about this one?

RCL F
ABS
X≠0?
RCL/ F
x

Dieter