CAS.numer; denom; lcoeff; degree... ??!! [It's OK NOW ! :o)]

[dg1969]

Han. You are absolutely irreplaceable ! Thank you for your endless patience.
I just found something you already knew. Integrated help does not give the exact syntax for the HOME side which is in fact different from the CAS side.


In CAS side:

Code:


froot((1+x^3)/(1+2*x))

is ok not need the second argument: 'x'

but it is essential in the "home" side. The aid does not indicate

expect for :

Code:


CAS.coeff("x^2+3-2*x","x","2")

(I am the only guilty 3 args clearly mentioned in the help)

so

Code:


CAS.froot("(1+x^2)/(2*x+x^3)","x")

or with a single string :

Code:


CAS.froot("(1+x^2)/(2*x+x^3),x") working perfectly !

It's the same thing for other commands that I mentioned...

Han, you know what ? You are my best cyber-friend :o)