Testing the mathjax engine
06-11-2017, 10:56 AM
Post: #6
 Csaba Tizedes Senior Member Posts: 501 Joined: May 2014
RE: Testing the mathjax engine
(02-19-2017 03:40 PM)Csaba Tizedes Wrote:
(05-08-2016 08:56 PM)emece67 Wrote:  From $$Q = mC\Delta T$$ you will get $$\Delta T = {Q\over mC}$$, with $$C=4182 {J\over kg \Delta K}$$ being the specific heat of water at 20ºC. With this you get $\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K$

Then the final temperature will be: $$T_0+\Delta T = 20 ºC + 2.989 \Delta K =$$ Inconsistent units.

$$\frac{N_i}{D_i}=\frac{N_{i-1}}{D_{i-1}}+\frac{1}{F_i}=\frac{F_i · N_{i-1}+D_{i-1}}{D_{i-1} · F_i}$$

JÍHÁÁÁÁ!

From these equations ($$\beta$$ in radian):
$$R_2 · \beta=2 · r · \pi$$, and

$$(R_2+s) · \beta=2 · R · \pi$$

we get:
$$R_2=\frac{\frac{h}{cos \alpha}}{\frac{R}{R-h_x}-1}$$, and

$$\beta=\frac{2 · (R-h_x) · \pi}{R_2}$$
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 Messages In This Thread Testing the mathjax engine - emece67 - 05-08-2016, 08:56 PM RE: Testing the mathjax engine - Csaba Tizedes - 02-19-2017, 03:33 PM RE: Testing the mathjax engine - Csaba Tizedes - 02-19-2017, 03:35 PM RE: Testing the mathjax engine - Csaba Tizedes - 02-19-2017, 03:40 PM RE: Testing the mathjax engine - Csaba Tizedes - 06-11-2017 10:56 AM RE: Testing the mathjax engine - Luigi Vampa - 02-19-2017, 08:14 PM

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