DDAYS in the solver

[Tim Wessman]

(10-21-2016 04:32 PM)moonbeam Wrote:  If the arguments of DDAYS are given, the function value is a constant. Solver can handle this just fine :-) Looking for the start or end date is another matter, best left to DateAdd(date,ndays).

Yes, you are right here of course. I was specifically thinking the "solve for any of the variables" aspect part of the solver like you point out. Thanks for the clarification!