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ArcTan(x,y)?
04-06-2017, 10:27 AM
Post: #18
RE: ArcTan(x,y)?
(04-05-2017 10:47 PM)KeithB Wrote:  I think I just stumbled across the problem you had:
arg(1+i1) is OK
arg(.1+i.1) is a syntax error
arg(0.1+i0.1) is OK
arg(.1+.1i) is OK

So you get the error when the decimal point is adjacent to i.

Implicit multiplication isn't supported:

arg(.1+i.1) is a syntax error
arg(.1+i*.1) ==> returns ARG(0.1+i*0.1); 0.79
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Messages In This Thread
ArcTan(x,y)? - toml_12953 - 04-05-2017, 12:07 PM
RE: ArcTan(x,y)? - Joe Horn - 04-05-2017, 12:20 PM
RE: ArcTan(x,y)? - toml_12953 - 04-05-2017, 12:26 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-05-2017, 03:00 PM
RE: ArcTan(x,y)? - toml_12953 - 04-05-2017, 03:39 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-05-2017, 06:22 PM
RE: ArcTan(x,y)? - KeithB - 04-05-2017, 07:28 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-05-2017, 07:47 PM
RE: ArcTan(x,y)? - KeithB - 04-05-2017, 10:47 PM
RE: ArcTan(x,y)? - DrD - 04-06-2017 10:27 AM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-06-2017, 03:22 PM
RE: ArcTan(x,y)? - KeithB - 04-05-2017, 07:33 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-05-2017, 07:53 PM
RE: ArcTan(x,y)? - KeithB - 04-05-2017, 08:10 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-05-2017, 09:17 PM
RE: ArcTan(x,y)? - jte - 04-05-2017, 09:08 PM
RE: ArcTan(x,y)? - KeithB - 04-05-2017, 09:42 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-05-2017, 10:38 PM
RE: ArcTan(x,y)? - KeithB - 04-05-2017, 10:41 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-06-2017, 03:30 PM
RE: ArcTan(x,y)? - Han - 04-06-2017, 03:53 PM
RE: ArcTan(x,y)? - JMB - 04-09-2017, 09:50 AM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-09-2017, 03:47 PM
RE: ArcTan(x,y)? - JMB - 04-09-2017, 08:00 PM
RE: ArcTan(x,y)? - KeithB - 04-06-2017, 02:38 PM
RE: ArcTan(x,y)? - StephenG1CMZ - 04-09-2017, 09:54 PM



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