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Contradiction between CAS and Home
07-09-2017, 10:46 AM
Post: #3
RE: Contradiction between CAS and Home
(07-09-2017 10:39 AM)toml_12953 Wrote:  
(07-09-2017 10:12 AM)COB160 Wrote:  In CAS mode if I type
(1-e^(-1/2))/(1-e^-2)
the result is
(e^(1/2))^3/((e^(1/2))^3+(e^(1/2))^2+(e^(1/2))+1)
wich is 0.174326466693

In home mode if I type the same
(1-e^(-1/2))/(1-e^-2)
the result is
0.455054233923 that is the result I was looking for.

How can this be possible?

I get 0.455... in both modes.

Type (1-e^(-1/2))/(1-e^-2) in CAS mode click enter and u will get (e^(1/2))^3/((e^(1/2))^3+(e^(1/2))^2+(e^(1/2))+1), then go to home-menu-get from CAS-enter to obtain the numerical value of the result
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RE: Contradiction between CAS and Home - COB160 - 07-09-2017 10:46 AM



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