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SIN(X)^COS(X)
11-26-2017, 03:41 PM
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SIN(X)^COS(X)
In function app, the plot is what I expect...defined over [0,pi),[2pi,3pi), etc. In advanced graphing app, I get an unexpected plot. Over (pi,2pi], I get a plot symmetric to [0,pi) with respect to the y axis, and and another plot of this interval mirrored below the x axis.

Why am I seeing this?

On the July version, (on my iPad) I can trace and display x,y values on this part (what I am expecting to be imaginary numbers) of the graph. On the beta on my physical unit, the plot is as described, but it will not allow me to trace a point on the unexpected part of the plot.
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Messages In This Thread
SIN(X)^COS(X) - lrdheat - 11-26-2017 03:41 PM
RE: SIN(X)^COS(X) - John Colvin - 11-26-2017, 08:01 PM
RE: SIN(X)^COS(X) - lrdheat - 11-27-2017, 03:09 AM
RE: SIN(X)^COS(X) - AlexFekken - 11-27-2017, 06:19 AM
RE: SIN(X)^COS(X) - lrdheat - 11-27-2017, 03:55 PM
RE: SIN(X)^COS(X) - Fortin - 11-28-2017, 02:52 PM
RE: SIN(X)^COS(X) - lrdheat - 11-29-2017, 03:19 AM
RE: SIN(X)^COS(X) - lrdheat - 11-29-2017, 02:37 PM
RE: SIN(X)^COS(X) - Fortin - 12-01-2017, 01:37 AM
RE: SIN(X)^COS(X) - lrdheat - 12-01-2017, 07:40 PM
RE: SIN(X)^COS(X) - chazzs - 12-04-2017, 10:17 PM
RE: SIN(X)^COS(X) - Fortin - 12-01-2017, 11:42 PM
RE: SIN(X)^COS(X) - lrdheat - 12-06-2017, 02:47 AM



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