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SIN(X)^COS(X)
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11-27-2017, 06:19 AM
Post: #4
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RE: SIN(X)^COS(X)
When sin(x) < 0 we have:
sin(x)^cos(x) = exp(cos(x)*ln(sin(x)) = exp(cos(x)*(i*pi + ln|sin(x)|)) = exp(i*pi*cos(x)) * |sin(x)|^cos(x) And the real part of exp(i*pi*cos(x)) is cos(pi*cos(x)) Does that explain what you see? |
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SIN(X)^COS(X) - lrdheat - 11-26-2017, 03:41 PM
RE: SIN(X)^COS(X) - John Colvin - 11-26-2017, 08:01 PM
RE: SIN(X)^COS(X) - lrdheat - 11-27-2017, 03:09 AM
RE: SIN(X)^COS(X) - AlexFekken - 11-27-2017 06:19 AM
RE: SIN(X)^COS(X) - lrdheat - 11-27-2017, 03:55 PM
RE: SIN(X)^COS(X) - Fortin - 11-28-2017, 02:52 PM
RE: SIN(X)^COS(X) - lrdheat - 11-29-2017, 03:19 AM
RE: SIN(X)^COS(X) - lrdheat - 11-29-2017, 02:37 PM
RE: SIN(X)^COS(X) - Fortin - 12-01-2017, 01:37 AM
RE: SIN(X)^COS(X) - lrdheat - 12-01-2017, 07:40 PM
RE: SIN(X)^COS(X) - chazzs - 12-04-2017, 10:17 PM
RE: SIN(X)^COS(X) - Fortin - 12-01-2017, 11:42 PM
RE: SIN(X)^COS(X) - lrdheat - 12-06-2017, 02:47 AM
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