imaginary unit (i) position on key

[Han]

(03-22-2018 02:59 PM)hpprime123 Wrote:  The connection between 1 and i is about a tenuous and arbitrary as the connection between pi and 1.


tenuous???
i = sqr(-1) = imaginary axis unit

And \( \cos(\pi) = 1 \), and \( \pi^0 = 1 \), and \( -e^{-i \pi } = 1 \), ...

So yes, tenuous given the infinite number of ways one can relate any two numbers. One case might be more useful to some people and not necessarily others (most high school students only work in the set of real numbers). This makes valuing one identity over any of the other identities arbitrary.