[VA] Short & Sweet Math Challenges #23: "May the 4th Be With You !" Special

11052019, 11:17 PM
(This post was last modified: 11052019 11:21 PM by Albert Chan.)
Post: #49




RE: [VA] Short & Sweet Math Challenges #23: "May the 4th Be With You !" ...
(11042019 07:18 PM)Jeff O. Wrote: My logic for this was as follows: Hi, Jeff O. I checked all (88) Armstrong numbers, and see how many A's can produce it. If B is an Armstrong number (B=C), A is unique → A,B has same sets of digits Confirmed (by brute force) that your conjecture is correct. 

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