How to evaluate A Taylor series at a specific value

08222018, 09:23 PM
Post: #23




RE: How to evaluate A Taylor series at a specific value
(08222018 08:50 PM)Han Wrote: Why would the evaluate of a function that contains an error term magically drop the error term? Exactly ! Taylor series that carried the error term should not be evaluable, at any x. The fact that taylor(sin(x))  x=0.5 can return anything is not right. Unless ... (see below) Quote:(x/x)  x=0 is indeterminate. The expression x/x is undefined at 0. It were meant to test the CAS order of evaluation. If CAS does evaluation before substitution, x/x simplied as 1 But, if CAS return 0/0, taylor(sin(x))  x=0.5 return sin(0.5) make sense. 

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