How to evaluate A Taylor series at a specific value
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08-23-2018, 02:30 PM
Post: #24
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RE: How to evaluate A Taylor series at a specific value
(08-22-2018 07:52 PM)parisse Wrote: | is evaluated more like a program, where x would be like an argument. If "|" is like running a program with argument x: taylor(sin(x))|x=0.5 ==> (lambda x: taylor(sin(x))) (0.5) ==> taylor(sin(0.5)) ==> sin(0.5) sin(x)|x=2 ==> (lambda x: sin(x))(2) ==> sin(2) Why does "|" hard to evaluate ? Why previous run of x := 1 affect it ? Maybe "|" is simply "evaluate at" ? However, that imply taylor had a bug (post #23) |
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