How to evaluate A Taylor series at a specific value

[Albert Chan]

(08-22-2018 07:52 PM)parisse Wrote:  It's hard to evaluate |. You don't want to get sin(1) for sin(x)|x=2 if x:=1; has been run,

(08-24-2018 06:21 AM)parisse Wrote:  This is wrong: x:=1 followed by sin(x)|x=2 returns sin(2), and that's not easy to evaluate

I am confused.

What situation will sin(x)|x=2 return sin(1) ?

Edit: Sorry for the noise. Above expression always return sin(2)