How to evaluate A Taylor series at a specific value
|
05-12-2018, 02:56 PM
(This post was last modified: 05-12-2018 02:58 PM by Joe Horn.)
Post: #8
|
|||
|
|||
RE: How to evaluate A Taylor series at a specific value
(05-12-2018 02:44 PM)DrD Wrote: (Variation on a theme): Hmmmm.... That seems to return sin(.5), not the desired result. Not sure why. Perhaps the x gets substituted right away, resulting in taylor(sin(.5))? <0|ΙΈ|0> -Joe- |
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 1 Guest(s)