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How to evaluate A Taylor series at a specific value
05-12-2018, 03:13 PM (This post was last modified: 05-12-2018 03:20 PM by DrD.)
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DrD Offline
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RE: How to evaluate A Taylor series at a specific value
I see what you mean. I tried it another way, and it seems to just return the SIN(x), not the taylor series evaluation. Oopsie!

Same thing if you make it into a function of x:

f(x):=taylor(SIN(x));
f(.5) ⇒ sin(.5) = 0.479425538604

Ignores the tayor() series expansion. Is that fair play, or bug?
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RE: How to evaluate A Taylor series at a specific value - DrD - 05-12-2018 03:13 PM



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