Easy as { 1 2 3 }? (when { 1 2 3 } ≠ { 1 2 3 })

[pier4r]

OT: request to David, could you improve the initial title? Google finds nothing and I had to resort to the MyBB search that is not totally bad if one has enough keywords
END OT.

Today I got for the first time a problem similar to this. On my 50g version 2.15 . Somehow one of my programs incremented a list until { 6. 6. } (n1) and another compared it to a list set to { 6. 6. } manually in a global variable and the 50g said "nope, they are different".

I checked with TYPE. Both are seen as type 5 and the numbers inside, the "6.", are type 0.

The funny part is that the second time that the program tries the comparison, it works. Don't ask me why. The first time it fails, the second time it works. I don't know how to fix it at the moment.

With SAME I get identical results (that is, the two lists are different).

n1: the subprogram starts with a list {1. 0.} and increments it until { 6. 6.} in base 7

update1: ok solved, I guess my beloved hp50g has a bit of problems. After a ON+F4 (test of the system) and a ON+F3 , now the system sees the two lists identical again.
update2: nope, somehow the program is behaving as before now. The two lists are different the first time, and equal the second time. Go figure...