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Solving sqrt(i)=z, one or two solutions?
10-25-2018, 10:52 AM
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RE: Solving sqrt(i)=z, one or two solutions?
z=sqrt(i) is a polynomial equation of degree 1 in z, therefore it has a unique solution. z^2=i is a polynomial equation of degree 2 in z, therefore it has 2 solutions (in C). This is what is called d'Alembert theorem (in France) or fundemental theorem of algebra in English speaking countries (I think).
I wonder how can sasa pretend that the Prime answer is unexpected.
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RE: Solving sqrt(i)=z, one or two solutions? - parisse - 10-25-2018 10:52 AM



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