Yet another Fibonacci mini-challenge (HP-42S/Free42)

[Thomas Klemm]

(12-05-2018 04:14 PM)Gerson W. Barbosa Wrote:  … if you notice that asinh(1/2) = ln(phi) then you can easily do it in ten steps.
… Hopefully I haven't spoiled the fun :-)

No worries, you just made me remember an older thread where the same trick is used to solve \(x(x+1)=2n\) (a.k.a. Inverse Little Gauss).
Similarly, we can use \(x (x-1) = 1 \) to calculate the golden ratio.

Kind regards
Thomas