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Little math problem(s) December 2018
12-19-2018, 09:20 PM
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RE: Little math problem December 2018
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Since 10^k - 1 ≡ 0 (mod 9) the result R is divisible by 9.
The smallest divisor of 9 greater than 1 is 3.

Cheers
Thomas
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RE: Little math problem December 2018 - Thomas Klemm - 12-19-2018 09:20 PM



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