factor(x^4+1) and partfrac(1/(x^4+1))
10-23-2019, 05:44 PM
Post: #13
 lrdheat Senior Member Posts: 860 Joined: Feb 2014
RE: factor(x^4+1) and partfrac(1/(x^4+1))
I am in the same boat. When I put a decimal point after the 1, I get the desired approximation, but cannot get the exact result with a square root symbol...
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 Messages In This Thread factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-21-2019, 02:05 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - goetz - 10-21-2019, 08:08 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Tim Wessman - 10-22-2019, 01:48 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-22-2019, 09:15 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Joe Horn - 10-22-2019, 10:33 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-23-2019, 04:10 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 12:08 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Joe Horn - 10-23-2019, 09:04 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - parisse - 10-22-2019, 02:57 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-23-2019, 04:05 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - parisse - 10-23-2019, 08:36 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-23-2019, 11:45 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Aries - 10-22-2019, 07:11 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - lrdheat - 10-23-2019 05:44 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - lrdheat - 10-23-2019, 05:46 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 06:03 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - parisse - 10-23-2019, 05:56 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - roadrunner - 10-23-2019, 06:03 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 06:07 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - roadrunner - 10-23-2019, 06:06 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - roadrunner - 10-23-2019, 07:15 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Thomas_Sch - 10-23-2019, 08:15 PM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - rombva - 10-24-2019, 09:34 AM RE: factor(x^4+1) and partfrac(1/(x^4+1)) - Tim Wessman - 10-24-2019, 09:59 AM