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(Free42) accuracy of LN1+X
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(Free42) accuracy of LN1+X
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(Free42) accuracy of LN1+X
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06-12-2020, 10:45 PM
(This post was last modified: 06-12-2020 11:24 PM by rprosperi.)
Post: #5
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RE: (Free42) accuracy of LN1+X
The function Werner is referring to is "LN1+X( )", so LN1+X(A) means evaluating that function for the value A.
This is a special version of the LN function for argument (meaning X) values very close to 0, which otherwise would not calculate as accurately. --Bob Prosperi |
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| Messages In This Thread |
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(Free42) accuracy of LN1+X - Werner - 06-12-2020, 03:23 PM
RE: (Free42) accuracy of LN1+X - Albert Chan - 06-12-2020, 06:51 PM
RE: (Free42) accuracy of LN1+X - grsbanks - 06-12-2020, 08:21 PM
RE: (Free42) accuracy of LN1+X - ijabbott - 06-13-2020, 11:07 AM
RE: (Free42) accuracy of LN1+X - johanw - 06-12-2020, 10:07 PM
RE: (Free42) accuracy of LN1+X - rprosperi - 06-12-2020 10:45 PM
RE: (Free42) accuracy of LN1+X - Albert Chan - 06-13-2020, 12:45 AM
RE: (Free42) accuracy of LN1+X - Paul Dale - 06-14-2020, 01:09 AM
RE: (Free42) accuracy of LN1+X - Albert Chan - 06-14-2020, 12:48 PM
RE: (Free42) accuracy of LN1+X - Paul Dale - 06-14-2020, 10:39 PM
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