(42, all flavours) Integer Division - how?

[Werner]

(12-13-2020 06:41 PM)Albert Chan Wrote:  Bonus: it removed the integer arguments requirement.

At the risk of being proven wrong again..
as long as b+1 is exact, (and q is not too large), the code for idiv3 works for fractional a and b, too, no?

function idiv3(a,b) -- assumed b > 0
local q, c = floor(a/b), b+1
a, b = a%b - a%c, q%c -- a-b = [2-2c, c-2]
if a==b or a==b-c then return q end
return q-1
end

Werner