No way to get an element free of brackets

[Albert Chan]

(02-13-2021 09:58 AM)essen Wrote:  lst2(i1):=lst1(i1);

I am not sure the question is, but above can be confused with function definition.

Perhaps you meant lst2[i1] := lst1[i1] ?

Or, if you really wanted to assign global variables to values (why ?)

CAS> lst1 := {1, 2, 3}
CAS> lst2 := {"myv1", "myv2", "myv3"}
CAS> FOR i1 FROM 1 TO 3 DO expr(lst2[i1] + ":=" + lst1[i1]); END;

CAS> myv1, myv2, myv3       → [1, 2, 3]