Free42 and cube root of complex number

02242021, 10:26 AM
Post: #6




RE: Free42 and cube root of complex number
(02242021 02:02 AM)Thomas Okken Wrote: atan2(0, 8) => pi, while atan2(0, 8) => pi pi < arg(z) ≤ pi Since polar form and rectangular form should match, I think 8 ± 0i should be adjusted to 8 + 0i = 8 exp(i*pi) For the same reason, sqrt(4  0i) = sqrt(4 + 0i) = 2i 4 [ENTER] 0 [COMPLEX] [+/] [SQRT] → 2i 

« Next Oldest  Next Newest »

Messages In This Thread 
Free42 and cube root of complex number  Ajaja  02232021, 11:05 PM
RE: Free42 and cube root of complex number  Thomas Okken  02242021, 02:02 AM
RE: Free42 and cube root of complex number  Albert Chan  02242021 10:26 AM
RE: Free42 and cube root of complex number  Paul Dale  02242021, 02:52 AM
RE: Free42 and cube root of complex number  JF Garnier  02242021, 08:28 AM
RE: Free42 and cube root of complex number  Werner  02242021, 08:59 AM
RE: Free42 and cube root of complex number  Thomas Okken  02242021, 01:35 PM
RE: Free42 and cube root of complex number  Albert Chan  02242021, 02:47 PM
RE: Free42 and cube root of complex number  Thomas Okken  02242021, 02:53 PM
RE: Free42 and cube root of complex number  Werner  02252021, 06:08 AM
RE: Free42 and cube root of complex number  Albert Chan  02252021, 04:40 PM

User(s) browsing this thread: 1 Guest(s)