Free42 and cube root of complex number
02-24-2021, 02:47 PM
Post: #8
 Albert Chan Senior Member Posts: 1,788 Joined: Jul 2018
RE: Free42 and cube root of complex number
(02-24-2021 01:35 PM)Thomas Okken Wrote:
(02-24-2021 08:59 AM)Werner Wrote:  Please, leave it as it is - Free42 would be one of the only ones to get it right ;-)

There is that! But the HP-42S doesn't support -0 ...

Hi, Thomas Okken

Can you elaborate what is decided ?

If Free42 do support -0, then sqrt(-4-0i) = sqrt(4*exp(-pi*i)) = 2*exp(-pi/2*i) = -2i

But, user need to know "-0" is actually inputed.
-0 should displayed as "-0", not "0"
-4-0*i should displayed as "-4 -i0", not "-4 i0"

If not, (-8-0i)^(1/3) = (-8+0i)^(1/3) = 1 + sqrt(3)*i
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 Messages In This Thread Free42 and cube root of complex number - Ajaja - 02-23-2021, 11:05 PM RE: Free42 and cube root of complex number - Thomas Okken - 02-24-2021, 02:02 AM RE: Free42 and cube root of complex number - Albert Chan - 02-24-2021, 10:26 AM RE: Free42 and cube root of complex number - Paul Dale - 02-24-2021, 02:52 AM RE: Free42 and cube root of complex number - J-F Garnier - 02-24-2021, 08:28 AM RE: Free42 and cube root of complex number - Werner - 02-24-2021, 08:59 AM RE: Free42 and cube root of complex number - Thomas Okken - 02-24-2021, 01:35 PM RE: Free42 and cube root of complex number - Albert Chan - 02-24-2021 02:47 PM RE: Free42 and cube root of complex number - Thomas Okken - 02-24-2021, 02:53 PM RE: Free42 and cube root of complex number - Werner - 02-25-2021, 06:08 AM RE: Free42 and cube root of complex number - Albert Chan - 02-25-2021, 04:40 PM

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