Pi Approximation Day
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07-26-2022, 01:38 PM
Post: #38
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RE: Pi Approximation Day
For \(p=5\) we get:
\( \begin{align} \sum_{n=1}^{\infty} \frac{1}{(n (n + 1))^5} = 126 - \frac{35 \pi^2}{3} - \frac{\pi^4}{9} \end{align} \) Depending on the number of terms used on the left-hand side, we get the following approximations for \(\pi\). \(0\): \( \begin{align} \sqrt{\frac{3}{2} \left(\sqrt{1729} - 35 \right)} \approx 3.14195300074 \end{align} \) \(\frac{1}{2^5}\): \( \begin{align} \sqrt{\frac{3}{8} \left(\sqrt{27662} - 140 \right)} \approx 3.14159418065 \end{align} \) \(\frac{1}{2^5}+\frac{1}{6^5}\): \( \begin{align} \frac{1}{6} \sqrt{\sqrt{5041398} - 1890} \approx 3.14159270392 \end{align} \) |
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