[hp50g] is it possible to solve linear systems with unknown variables in it?

[ijabbott]

You can also divide a vector by a square matrix. Really, it multiplies by the inverse of the matrix.

1. Put the right hand side on the stack as a 2x1 matrix:

Code:

[[0] [2]]

2. Put the X and Y coefficients on the stack as a 2x2 matrix:

Code:

[[7 '2*K'] ['3*K' -8]]

3. Divide. Result is a 2x1 matrix. The first row is X, the second row is Y:

Code:

[[ '2*K/(3*K^2+28)' ]
 [ '-14/(6*K^2+56)' ]]

(I don't know why it doesn't factor out the 2 from the numerator and denominator for the 2nd row.)