(35S) Quick integration

[Roberto Volpi]

Dear Pedro,

here a short and quick example.

f(x)=∫√(1+4X^2)dx in interval [0,1]

which can be interpreted as the arc length of the parabola y=x^2 in interval [0,1]

With the native HP35S integrator, after approx 1 minute and 37 seconds:
=1.47894285754

With this program, after 1 second:
=
stack y: 0.5
stack x: 1.48215537045

Please take into account that also the value of the native HP35S integrator is approximate.