(35S) Quick integration
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11-19-2022, 04:58 AM
Post: #23
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RE: (35S) Quick integration
(11-19-2022 01:42 AM)Liamtoh Resu Wrote: Can someone walk me through the symbolic calculation of the function? ∫(sqrt(1+4*x^2) dx) // let y=2x, dy = 2 dx = ∫(sqrt(1+y^2) (dy/2)) // let y=sinh(z), dy = cosh(z) dz = ∫(cosh(z) (cosh(z)/2 dz)) = ∫((1+cosh(2z))/4 dz) // cosh(z)^2 = (1+cosh(2z))/2 = (z + sinh(2z)/2)/4 // sinh(2z) = 2*sinh(z)*cosh(z) = (z + sinh(z)*cosh(z))/4 ∫(x = 0 .. 1) = ∫(y = 0 .. 2) = ∫(z = 0 .. asinh(2)) = (asinh(2) + 2*sqrt(5))/4 ≈ 1.47894285754 |
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