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Integration by substitution: how to ?
10-10-2014, 01:37 PM
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RE: Integration by substitution: how to ?
assume(u>0); a:=subst('integrate(1/(x+sqrt(x)),x)',x=u^2);
a;
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RE: Integration by substitution: how to ? - parisse - 10-10-2014 01:37 PM



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