Integration by substitution: how to ?

10102014, 01:37 PM
Post: #2




RE: Integration by substitution: how to ?
assume(u>0); a:=subst('integrate(1/(x+sqrt(x)),x)',x=u^2);
a; 

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Integration by substitution: how to ?  Aries  10102014, 10:47 AM
RE: Integration by substitution: how to ?  parisse  10102014 01:37 PM
RE: Integration by substitution: how to ?  Aries  10112014, 08:16 AM

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