Using SLOPE function in Function APP with CAS defined function

12102014, 11:49 AM
Post: #8




RE: Using SLOPE function in Function APP with CAS defined function
(12092014 03:01 PM)Han Wrote: Edit: The command f:=g+h; is the same as f(x):=g(x)+h(x). If you had wanted to create \( f(x) = x^2 + 3t+1 \) so that the \( t \) is a constant with respect to \( x \), then type: f(x):=g(x)+h(t); as the right hand side is an expression in terms of x and t, and the := operator creates a function with only x as the variable as specified by the (x) after f.Unfortunately, it's a little more tricky, f:=g+h is not equivalent to f(x):=g(x)+h(x). The reason is that when you write f(x):=g(x)+h(x), the right handside is not evaled, g and h are not replaced by their value, if g or h is modified, f will reflect the modification. 

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Messages In This Thread 
Using SLOPE function in Function APP with CAS defined function  cdecastro  12082014, 06:43 PM
RE: Using SLOPE function in Function APP with CAS defined function  mpowell@rogershsa.com  12092014, 03:58 AM
RE: Using SLOPE function in Function APP with CAS defined function  DrD  12092014, 02:26 PM
RE: Using SLOPE function in Function APP with CAS defined function  cdecastro  12092014, 02:46 PM
RE: Using SLOPE function in Function APP with CAS defined function  Han  12092014, 03:01 PM
RE: Using SLOPE function in Function APP with CAS defined function  parisse  12102014 11:49 AM
RE: Using SLOPE function in Function APP with CAS defined function  Han  12092014, 02:52 PM
RE: Using SLOPE function in Function APP with CAS defined function  DrD  12092014, 04:26 PM

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