Programming Challenge: a classic trigonometry problem

[Thomas Klemm]

(01-06-2014 12:23 AM)Gerson W. Barbosa Wrote:  Same as Bunuel's method, I think.

Wikipedia provides yet another solution: Crossed ladders problem
\[ x^3(x-c)=1 \]
Which leads to:
\[ x=\frac{1}{x^3}+c \]
This equation can be solved iterating the following program:

001 \(x^3\)
002 1/x
003 RCL+ C

For C use: \(\frac{60}{\sqrt{700}}\).
Start with x = 2.
After 12 runs the value doesn't change anymore: 2.34530476375
Can it be any shorter?

Cheers
Thomas