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Quiz: calculating a definite integral
01-03-2014, 06:08 AM (This post was last modified: 01-03-2014 06:11 AM by walter b.)
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RE: Quiz: calculating a definite integral
(01-03-2014 05:18 AM)Thomas Klemm Wrote:  
(01-02-2014 11:39 PM)Bunuel66 Wrote:  iterating: \(\int_{0}^{1}x^n\log(x)^n dx=\frac{(-1)^n n!}{n^n}\)
This should be: \(\int_{0}^{1}x^n\log(x)^n dx=\frac{(-1)^n n!}{(n+1)^{n+1}}\)

Then you won't run into problems with \(0^0\).

'This should be' ?? Christmas is over. Both formulas don't mean the same, there can be only one correct.

d:-?
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RE: Quiz: calculating a definite integral - walter b - 01-03-2014 06:08 AM



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