Quiz: calculating a definite integral

[Thomas Klemm]

(01-03-2014 09:04 PM)Bunuel66 Wrote:  Don't get the point, \(\exp(-\infty)\)=0.

The domain of \(\exp(x)\) is \(\mathbb{R}\), but \(-\infty \notin \mathbb{R}\). Thus you can not just plug \(-\infty\) into the Taylor-series of this function and expect everything works. You can calculate \(\lim_{x\to\infty}\exp(x)\) but that's not the same as \(\exp(-\infty)\). This expression is just not defined.

HTH
Thomas