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little problem with CAS
01-30-2015, 01:00 PM (This post was last modified: 01-30-2015 06:18 PM by Hlib.)
Post: #9
RE: little problem with CAS
(01-30-2015 08:40 AM)Angus Wrote:  ... but I can't figure out how 0.2*a^32 converts to a^32/(a-1) ?

Thank you
\[\frac{a^{32}-1}{a-1}-\frac{a^{32}*(a-1)}{5*{(a-1)}}\]
\[\frac{a^{32}-1}{a-1}-\frac{a^{32}*(6-1)}{5*{(a-1)}}=\frac{-1}{a-1}\]
\[\frac{a^{32}-1}{a-1}-\frac{a^{32}}{a-1}=\frac{-1}{a-1}\]
Thomas Klemm forgot to write "5". Wink This is a groundless mathematical trick, but the result is really true.
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Messages In This Thread
little problem with CAS - Hlib - 01-25-2015, 08:52 PM
RE: little problem with CAS - Mark Hardman - 01-25-2015, 09:04 PM
RE: little problem with CAS - Hlib - 01-25-2015, 09:53 PM
RE: little problem with CAS - Thomas Klemm - 01-25-2015, 10:17 PM
RE: little problem with CAS - Hlib - 01-26-2015, 08:22 AM
RE: little problem with CAS - rprosperi - 01-26-2015, 01:23 AM
RE: little problem with CAS - Angus - 01-30-2015, 08:40 AM
RE: little problem with CAS - Hlib - 01-30-2015 01:00 PM



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