Circle with interior arc segments

[DrD]

Han,

Thomas has the right idea. For this purpose, there is only one circle segment for each of the 6 radii, that is to intersect the semi-circle tangent to its i*30° point. The segments are to be totally contained within the interior of the semi-circle.

The radius of those 6 circle segments was my difficulty, (since the two points are known), but two points don't determine a circle, and it just got deeper the more I worked with the problem. Thomas worked it out, nicely. Now if I could get a wrench on how to keep the arc lengths between the right hand edge, and it's semi-circle-circumference tangent, it would be a good day!

I can still hear my calculus professor, "Dale, your problem is you need to take a geometry class!" That was in 1966, and she was exactly right!

-Dale-