Brain Teaser - Area enclosed by a parabola and a line
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09-13-2015, 10:06 PM
(This post was last modified: 09-14-2015 09:49 AM by Bunuel66.)
Post: #7
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RE: Brain Teaser - Area enclosed by a parabola and a line
Sorry to restate what Gerson has already provided. That said I haven't used a quadratic solver ;-) Just a mix of hand computations and checks with a CAS software (the one included in Geogebra).
May I suggest: h(x)=[64x⁶+48x⁴+12x²+1]/48x³=(4x²+1)³/48x³ h(1)=125/48~2.604 With a minimum for h(x) at x=0.5 of 4/3 My 2 cents. Regards |
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