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Brain Teaser - Area enclosed by a parabola and a line
09-13-2015, 10:06 PM (This post was last modified: 09-14-2015 09:49 AM by Bunuel66.)
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RE: Brain Teaser - Area enclosed by a parabola and a line
Sorry to restate what Gerson has already provided. That said I haven't used a quadratic solver ;-) Just a mix of hand computations and checks with a CAS software (the one included in Geogebra).

May I suggest: h(x)=[64x⁶+48x⁴+12x²+1]/48x³=(4x²+1)³/48x³

h(1)=125/48~2.604

With a minimum for h(x) at x=0.5 of 4/3

My 2 cents.

Regards
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RE: Brain Teaser - Area enclosed by a parabola and a line - Bunuel66 - 09-13-2015 10:06 PM



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