sqrt(1+i)
|
07-04-2021, 03:50 PM
Post: #18
|
|||
|
|||
RE: sqrt(1+i)
(10-05-2016 12:16 PM)roadrunner Wrote: Code is wrong. Think polar form (cis(θ) = cos(θ) + i*sin(θ)) z = |z| * cis(arg(z)) √z = √|z| * cis(arg(z)/2) With arg(z) = [-pi,pi], sign(arg(z)) = sign(sin(arg(z)) → sign(im(z)) = sign(im(√z)) CAS> csqrt(z) := √((abs(z)+re(z))/2) + sign(im(z))*i*√((abs(z)-re(z))/2) CAS> csqrt(1+i) \(\displaystyle \sqrt{\frac{1}{2} \cdot (\sqrt{2}+1)}+ i \sqrt{\frac{1}{2} \cdot (\sqrt{2}-1)}\) CAS> csqrt(Ans) \(\displaystyle i \sqrt{\frac{1}{2} \cdot (-\sqrt{\frac{1}{2} \cdot (\sqrt{2}+1)}+2^{\frac{1}{4}})}+\sqrt{\frac{1}{2} \cdot (\sqrt{\frac{1}{2} \cdot (\sqrt{2}+1)}+2^{\frac{1}{4}})}\) CAS> approx(Ans) → 1.06955393236+0.212747504727*i CAS> Ans^4 → 1+i Also, with radical not simplified, mess exploded with nested square root. CAS> rootroot(1+i, 1) \(\displaystyle \frac{i \sqrt{\sqrt{2}-1}}{\sqrt{2}}+\frac{\sqrt{2} \cdot \frac{1}{2}}{\sqrt{\sqrt{2}-1}}\) CAS> rootroot(Ans, 1) \(\displaystyle \frac{1}{2} \cdot \frac{\sqrt{\sqrt{2}-1}}{\sqrt{\frac{1}{2} \cdot (2 \sqrt{\frac{1}{4} \cdot (\left(\frac{\sqrt{2}}{\sqrt{\sqrt{2}-1}}\right)^{2}+4 \left(\frac{\sqrt{\sqrt{2}-1}}{\sqrt{2}}\right)^{2})}-\frac{\sqrt{2}}{\sqrt{\sqrt{2}-1}})}}+\frac{i \sqrt{\frac{1}{2} \cdot (2 \sqrt{\frac{1}{4} \cdot (\left(\frac{\sqrt{2}}{\sqrt{\sqrt{2}-1}}\right)^{2}+4 \left(\frac{\sqrt{\sqrt{2}-1}}{\sqrt{2}}\right)^{2})}-\frac{\sqrt{2}}{\sqrt{\sqrt{2}-1}})}}{\sqrt{2}}\) CAS> approx(Ans) → 1.06955393236+0.212747504727*i |
|||
« Next Oldest | Next Newest »
|
Messages In This Thread |
RE: sqrt(1+i) - parisse - 09-26-2016, 06:19 PM
RE: sqrt(1+i) - Helge Gabert - 09-26-2016, 08:33 PM
RE: sqrt(1+i) - dg1969 - 09-26-2016, 08:38 PM
RE: sqrt(1+i) - Helge Gabert - 09-27-2016, 04:19 AM
RE: sqrt(1+i) - Helge Gabert - 10-04-2016, 03:06 PM
RE: sqrt(1+i) - Helge Gabert - 10-04-2016, 04:50 PM
RE: sqrt(1+i) - roadrunner - 10-05-2016, 12:16 PM
RE: sqrt(1+i) - Albert Chan - 07-04-2021 03:50 PM
RE: sqrt(1+i) - roadrunner - 07-07-2021, 01:35 PM
RE: sqrt(1+i) - parisse - 10-05-2016, 01:52 PM
RE: sqrt(1+i) - DedeBarre - 10-05-2016, 05:54 PM
RE: sqrt(1+i) - Hlib - 07-05-2021, 05:31 PM
|
User(s) browsing this thread: 1 Guest(s)