Solver Problem 'Maybe'
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01-04-2017, 05:17 PM
Post: #1
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Solver Problem 'Maybe'
Below is the equation for a Circle.
R^2=(X-H)^2+(Y-K)^2. The solver will solve for R=7.2801. X=4, H=2, Y=-6 and K=1 R^2=53. You can solve any of the variables except 'X'. Solving for X returns '0'. Re-arranging the formulae to solve for X. Note: SQRT below instead squareRoot sign on calculator. X=H+SQRT-(K^2-2*Y*K-(R^2-Y^2)). Note: 'H+' Now I can solve for any variables including 'X'. 2+2=4 Of course using X=H-SQRT-(K^2-2*Y*K-(R^2-Y^2)). Note: 'H-' cannot solve for X either, since -SQRT-(K^2-2*Y*K-(R^2-Y^2))=-2. 2-2=0 Which may be a clue????? Its seems that the Solver precedes the SQRT sign with H- instead of H+ and returns '0' instead of '4'. The other option is, maybe I've had too much to drink over the Holidays. Thanks BM |
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Messages In This Thread |
Solver Problem 'Maybe' - BERNARD MICHAUD - 01-04-2017 05:17 PM
RE: Solver Problem 'Maybe' - roadrunner - 01-05-2017, 02:36 PM
RE: Solver Problem 'Maybe' - BERNARD MICHAUD - 01-05-2017, 05:11 PM
RE: Solver Problem 'Maybe' - Nigel (UK) - 01-05-2017, 06:27 PM
RE: Solver Problem 'Maybe' - BERNARD MICHAUD - 01-05-2017, 07:36 PM
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