Programming Exercise (HP-15C, 15C LE - and others)

[Thomas Klemm]

(03-29-2014 12:32 PM)Tugdual Wrote:  For (b) I did:
$$\sum _{ K=10000 }^{ 1 }{ \frac { { (-1 })^{ K+1 } }{ K } }$$

I can't explain the difference because the result is the same

That's interesting! Thus the order doesn't seem to be changed.
Could you try the following (similar to Gerson's 2nd example on the HP-50g):
$$\sum_{K=1}^{10000}{\frac{{(-1})^{K}}{10001-K}}$$

Thanks
Thomas

PS: When I tried this on the emulator I got:
Error: Invalid input
IIRC this was an issue with the original firmware which was fixed meanwhile.
I didn't bother to upgrade. Is a new version of the emulator available?