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nop operation?
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10-28-2017, 10:52 AM
Post: #5
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RE: nop operation?
Xcas
[subst((abs(2*x-1)) = 1,'abs','nop'), subst((abs(2*x-1)) = 1,'abs','neg')] returns [(2*x-1) = 1, (-2*x+1) = 1] http://www.hpmuseum.org/forum/thread-857...hlight=nop |
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nop operation? - webmasterpdx - 10-26-2017, 02:30 PM
RE: nop operation? - parisse - 10-26-2017, 02:54 PM
RE: nop operation? - webmasterpdx - 10-26-2017, 10:42 PM
RE: nop operation? - parisse - 10-27-2017, 06:04 AM
RE: nop operation? - compsystems - 10-28-2017 10:52 AM
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