HP 15C and INT(1/√(1x),0,1)

01082018, 10:15 PM
Post: #9




RE: HP 15C and INT(1/√(1x),0,1)
(01082018 04:07 PM)salvomic Wrote: I could try a confrontation between a classic and a Limited edition HP15. The indefinite integral is –2√(1–x) so the integral from 0 to 1 is exactly 2. (01082018 04:07 PM)salvomic Wrote: After 50 mins the classic 15C (FIX 4) was still running, instead the LE (FIX 6) gave up with “Error 0” message ("Improper mathematics operation": why?) You can find out yourself: as soon as the error occurs, switch to program mode an see at which line you are. Since the stack is filled with x, press R↓ to check x. I suspect that the error is caused by the 1/x instruction, and this may happen if x is so close to 1 that 1–x is evaluated to zero, which leads to an attempt to divide by zero. But this is just a guess. ;) This usually does not happen as the interval should not be evaluated at its limits. But if Δx eventually becomes extremely small this may well be possible. Dieter 

« Next Oldest  Next Newest »

User(s) browsing this thread: 1 Guest(s)