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The new dfc and dfc2f functions in action
01-11-2018, 07:23 AM (This post was last modified: 01-11-2018 07:27 AM by salvomic.)
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RE: The new dfc and dfc2f functions in action
(01-11-2018 02:33 AM)Joe Horn Wrote:  It seems that you may have been looking for where the decimal expansions of the inputs begin to differ. Don't do that. Look instead at the outputs of dfc and see where THOSE begin to differ. The entire algorithm is illustrated in the above screen shot. The decimal expansions have nothing to do with it.

Well, thank you. Understood now.
I confronted 6 and 4, but increased 6 to 7 and not 4 to 5...

Salvo

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RE: The new dfc and dfc2f functions in action - salvomic - 01-11-2018 07:23 AM



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