Differential Equation Entry?

04102018, 11:14 AM
Post: #1




Differential Equation Entry?
How can this be solved using the prime: (Ideally, returning BOTH a general and a particular solution.)
(y*e^x) dx + (y^2  1) dy = 0, AND y(0) = 1 Desired results: y^2  ln(y^2) = 2*e^x + c1; {General Solution} y^2  ln(y^2) = 2*e^x + 3; {Particular solution} 

04102018, 11:53 AM
Post: #2




RE: Differential Equation Entry?
desolve(y*exp(x)+(y^21)*y'=0) returns the implicit equation for the solutions (in display and if you interpret fsolve).
odesolve will solve this equation numerically, but not for this initial condition, because CauchyLipschitz is not verified if y=1 (you can not express y' in terms of x and y). 

04102018, 01:22 PM
Post: #3




RE: Differential Equation Entry?
(04102018 11:53 AM)parisse Wrote: desolve(y*exp(x)+(y^21)*y'=0) returns the implicit equation for the solutions (in display and if you interpret fsolve). Thanks, Bernard! I tried lots of other ways, but not that one, and I spent way too much time trying them! Dale 

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