Post Reply 
[BASIC HELP] Equations on HP Prime
03-05-2019, 04:03 PM
Post: #1
[BASIC HELP] Equations on HP Prime
Hello there!
First, I would like to apologize for such a noob question.
I don't know if this is possible - probably it's but I'm to stupid to find it myself: how can I """de-siplify""" (I really don't know how to properly call this) an equation?
Let's say I have (a+b)^2, where can I put it to see a^2+2ab+b^2?
I know about the Solve app but if I'm right I need to give a value to the variables to solve one of them, e.g set b=3 in (a+b)^2.

Thanks in advance for the help.
If this question still confusing, I can try to explain it better in the comments.
Find all posts by this user
Quote this message in a reply
03-05-2019, 05:08 PM (This post was last modified: 03-05-2019 05:35 PM by StephenG1CMZ.)
Post: #2
RE: [BASIC HELP] Equations on HP Prime
In CAS, "simplify((a+b) squared)" gives "a squared + 2ab + b squared"
Where squared = tap the x squared key
(Unless a and b have been given numerical values)

And factor() or collect() takes you back.

Stephen Lewkowicz (G1CMZ)
https://my.numworks.com/python/steveg1cmz
Visit this user's website Find all posts by this user
Quote this message in a reply
03-05-2019, 05:42 PM
Post: #3
RE: [BASIC HELP] Equations on HP Prime
If you have purged a, and b so that they are purely symbolic then:

[CAS]

(a+b)^2 == > (a+b)^2
expand((a+b)^2) ==> 2*a*b+a^2+b^2
collect(2*a*b+a^2+b^2) ==> (a+b)^2

-Dale-
Find all posts by this user
Quote this message in a reply
03-05-2019, 06:41 PM
Post: #4
RE: [BASIC HELP] Equations on HP Prime
(03-05-2019 04:03 PM)fpicoral Wrote:  Hello there!
First, I would like to apologize for such a noob question.
I don't know if this is possible - probably it's but I'm to stupid to find it myself: how can I """de-siplify""" (I really don't know how to properly call this) an equation?
Let's say I have (a+b)^2, where can I put it to see a^2+2ab+b^2?
I know about the Solve app but if I'm right I need to give a value to the variables to solve one of them, e.g set b=3 in (a+b)^2.

Thanks in advance for the help.
If this question still confusing, I can try to explain it better in the comments.

Expand(expr) Wink
Best,

Aries Smile
Find all posts by this user
Quote this message in a reply
Post Reply 




User(s) browsing this thread: 1 Guest(s)