Post Reply 
Sine of the times.
06-22-2024, 08:42 PM
Post: #21
RE: Sine of the times.
(06-12-2024 08:58 PM)Nigel (UK) Wrote:  Gauss found this odious, because he felt that \(\sin^2(x)\) should mean \(\sin(\sin(x))\) (and he has a point!) but since the repeated sine is used so rarely this isn't an issue in practice.

Nigel (UK)

(Added) Just to confuse things, \(\sin^{-1}x\) means the inverse sine of \(x\), not \(1/\sin(x)\)!

Some years ago I had a German student who told me that in Germany, they are taught that \(f^2(x)\) means \(f(f(x))\). When I asked her about \(\sin^2(x)\) she said that trig functions were special exceptions.

I thought this was rather odd until it occurred to me that this is exactly what we do with derivatives: \({d^2\over dx^2} f(x)\) means \({d\over dx}{d\over dx} f(x)\). The point you make about \(\sin^{-1}x\) is consistent with this notation.


The nth derivative is often denoted \(f^{(n)}(x)\) with the n in parentheses. Using this notation, I have seen \(f^{(0)}(x)\) (the zeroth derivative) to mean \(f(x)\) and \(f^{(-1)}(x)\) (the inverse derivative) to mean the antiderivative of \(f(x)\).
Find all posts by this user
Quote this message in a reply
06-22-2024, 08:55 PM
Post: #22
RE: Sine of the times.
(06-12-2024 08:58 PM)Nigel (UK) Wrote:  (Added) Just to confuse things, \(\sin^{-1}x\) means the inverse sine of \(x\), not \(1/\sin(x)\)!

I tell my students, whatever you do, don't ever write \(\sin^{-2}x\).
Possible meanings:
  • \(\sin^{-1}(\sin^{-1}(x))\)
  • \((\sin^{-1}(x))^2\)
  • \(1 \over \sin^2(x) \)
Find all posts by this user
Quote this message in a reply
Post Reply 




User(s) browsing this thread: 1 Guest(s)