Python round() broken
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04-17-2021, 07:08 PM
(This post was last modified: 04-19-2021 07:47 AM by Guenter Schink.)
Post: #1
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Python round() broken
Is it just my G2 to show this error in Python?
round(3/7,6) ==> 0.4285709999999999 (if I counted the 9s correctly) should be 0.2428571 similar error with round(5/7,6) round(3/11,6) round(5/11,6 round(7/11,6) previously in my post a first digit "2"crept in inadvertently The virtual calculator 64bit doesn't show this behavior. Günter PS: of course reported to calcbeta too |
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04-17-2021, 08:48 PM
Post: #2
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RE: Python round() broken
(04-17-2021 07:08 PM)Guenter Schink Wrote: Is it just my G2 to show this error in Python? Wow! Your calculator is really off! I get 0.4285709999999999 ![]() Tom L Cui bono? |
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04-17-2021, 11:10 PM
Post: #3
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RE: Python round() broken
(04-17-2021 08:48 PM)toml_12953 Wrote:(04-17-2021 07:08 PM)Guenter Schink Wrote: Is it just my G2 to show this error in Python? grrr.. typo - first digit "2" shouldn't be there. But what would you expect with rounding to 6 digits? The result should be 0.428571 Günter |
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04-18-2021, 12:32 AM
(This post was last modified: 04-18-2021 12:33 AM by toml_12953.)
Post: #4
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RE: Python round() broken
(04-17-2021 11:10 PM)Guenter Schink Wrote:Yes, You added an extra 2. I knew that it wasn't your calculator, hence the smiley.(04-17-2021 08:48 PM)toml_12953 Wrote: Wow! Your calculator is really off! I get Tom L Cui bono? |
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04-19-2021, 09:48 AM
Post: #5
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RE: Python round() broken
Hello,
I have literally NO clue as to what is going on there! Works on emulator, works on prime G1... but prime G2 fails! Something buried deep in the float library or something like that? Note that Python uses doubles... As such, these are binary numbers... not BCD... so things like rounding will/Can yeild unexpected results... Cyrille Although I work for the HP calculator group, the views and opinions I post here are my own. I do not speak for HP. |
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