Chudnovsky algorithm

08172021, 02:50 AM
Post: #1




Chudnovsky algorithm
PI_ (n):=((2.0*sqrt(2)/9801)*Σ((4*k)!*
(1103+26390*k)/((k!)^4*396^(4*k)),k,0,n))^(1); Why the evaluation at different values of n doesn't change the decimal values? PI_ (1) [enter] 3.14159265359 PI_ (10) [enter] 3.14159265359 PI_ (34) [enter] 3.14159265359 

08172021, 04:30 AM
Post: #2




RE: Chudnovsky algorithm
(08172021 02:50 AM)compsystems Wrote: PI_ (n):=((2.0*sqrt(2)/9801)*Σ((4*k)!* First of all, this is one of Ramanujan formulae for computing Pi. Secondly, you're not getting changes because just 1 term of the series already gives the accuracy your system allows. Use some multiprecision system and you'll see them change. Estas matando moscas a cañonazos. V. All My Articles & other Materials here: Valentin Albillo's HP Collection 

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